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4y^2-30y-54=0
a = 4; b = -30; c = -54;
Δ = b2-4ac
Δ = -302-4·4·(-54)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-42}{2*4}=\frac{-12}{8} =-1+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+42}{2*4}=\frac{72}{8} =9 $
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